Teaching Of Algebra At Upper Primary Level
(Std.VI to VIII)
What Are
Single Variable Equations?
To
understand a single variable equation, let us break it into its two components:
the variable and the equation.
A
variable is a symbolic placeholder for a number we do not yet know. It’s
very common to see x or y used as a variable in math
problems, but variables can be represented by any symbol or letter.
x+4=14
In this
case, x is our variable. It represents a number that is currently
unknown.
An
equation sets two mathematical expressions equal to one another. This equality
is represented with an equals sign (=) and each side of the expression can be
as simple as a single integer or as complex as an expression with multiple
variables, exponents, or anything else.
The above
is an example of an equation. Each side of the expression equals the other.
So if we
put together our definitions, we know that:
A single
variable equation is an equation in which there is only one variable
used. (Note: the variable can be used multiple times and/or used on either side
of the equation; all that matters is that the variable remains the same.)
6x+3−2x=19
4y−2=y+7
These are
all examples of single variable equations. You can see how some expressions
used the variable multiple times or used the variable in both expressions
(on either side of the equals sign).
No matter
how many times the variable is used, these still count as single variable
problems because the variable remains constant and there are no other
variables.
How to
Manipulate a Single Variable Equation
In order
to solve a single variable equation, we must isolate our variable on one side
of the equation. And the way we do this is by shifting the rest of our terms to
the other side of the equation.
In order
to shift our terms (numbers), we must therefore cancel them out on their
original side by performing the opposite function of the term.
Opposite
function pairs are:
1.
Addition and subtraction
2.
Multiplication and division
So if we have a
term on one side that has a plus sign (addition), we must subtract that
same amount from both sides.
x+2=6
x+2−2=6−2
x=4
If we have a
term that is multiplied, we must divide that same amount from both
sides.
3x = 18
x=6
Formulae for Squares :
·
(a + b)2 = a2 + 2ab
+ b2
·
(a – b)2 = a2 – 2ab
+ b2
·
a2 + b2 = (a + b)2 –
2ab
·
a2 – b2 = (a – b)(a
+ b)
·
(a + b + c)2 = a2 +
b2 + c2 + 2ab + 2bc + 2ca
·
(a – b – c)2 = a2 +
b2 + c2 – 2ab + 2bc – 2ca
·
An
algebraic expression is a mathematical phrase that contains integral or
fractional constants
(numbers), variables (alphabets)
and algebraic operators (such
as addition, subtraction, division, multiplication, etc.) operating on them.
Also, these expressions are expressed in the form of term, factor and
coefficient.
a +
1, a
+ b, x2 + y, 5x/2, etc. are few
examples of the algebraic expressions. The
algebraic expressions are readily used as a number of mathematical formulas and
find usage in generalizing them.
we will
learn about the different elements forming these expressions – terms, its
factors and coefficient.
Terms of
an Expression
A term is
a number, a variable, product of two or more variables or product of a number
and a variable. An algebraic expression is formed by a single term or by a
group of terms. For example, in the expression 4x + y, the two terms are
4x and y.
It is to
be noted here that terms add up to form an expression. Say there is a term 8xy,
which is the product of 8, x and y. There is
another term -4z, which is the product of -4 and z. On
adding them up, 8xy + (-4z), we get 8xy – 4z,
which is an algebraic expression.
Factor of
a Term
- The numbers or variables
that are multiplied to form a term are called its factors. Example, 5xy is a term with factors
5, x and y.
- The factors cannot be
further factorized. Example, 5xy cannot
be written as the product of factors 5 and xy. This is because xy can be factorized to x and y.
- The factors of the
term 3a4 are
3, a, a, a and a.
- 1 is not taken as a separate
factor.
Coefficient
of a Term
A
coefficient is the numerical factor of a term containing constant and
variables.
- In the term 5ab, 5 is the coefficient.
- -5 is the coefficient of the
term –5ab2.
- When there is no numerical
factor in a term, its coefficient is taken as +1. For example, in the
term x2y3,
the coefficient is +1.
- In the term –x, the coefficient is -1.
- A coefficient is sometimes
generalized as either the numerical factor, variable factor or the
products of the two. As for example, in the term 5ab2, b is the
coefficient of 5ab.
Similarly, in 10ab, -2a is the coefficient of -5b and so on.
What is a
Coefficient in Maths?
A coefficient is an integer that is written along
with a variable or it is multiplied by the variable. For example, in the term
2x, 2 is the co-efficient.
Those
variables which do not carry any number along with them have a coefficient 1.
For example, the term y has coefficient 1.
In linear
algebra, when we write the equations, the coefficients always exist for
variables.
Expansion Formulae
list of Algebraic Expansion formulas –
- a2 –
b2 = (a – b)(a + b)
- (a+b)2 =
a2 + 2ab + b2
- a2 +
b2 = (a + b)2 – 2ab
- (a –
b)2 = a2 – 2ab + b2
- (a +
b + c)2 = a2 + b2 + c2 +
2ab + 2bc + 2ca
- (a –
b – c)2 = a2 + b2 + c2 –
2ab + 2bc – 2ca
- (a +
b)3 = a3 + 3a2b + 3ab2 +
b3 ; (a + b)3 = a3 + b3 +
3ab(a + b)
- (a –
b)3 = a3 – 3a2b + 3ab2 –
b3
- a3 –
b3 = (a – b)(a2 + ab + b2)
- a3 +
b3 = (a + b)(a2 – ab + b2)
- (a +
b)4 = a4 + 4a3b + 6a2b2 +
4ab3 + b4
- (a –
b)4 = a4 – 4a3b + 6a2b2 –
4ab3 + b4
- a4 –
b4 = (a – b)(a + b)(a2 + b2)
- a5 –
b5 = (a – b)(a4 + a3b + a2b2 +
ab3 + b4)
- If n
is a natural number an – bn =
(a – b)(an-1 + an-2b+…+ bn-2a + bn-1)
- If n
is even (n = 2k), an + bn =
(a – b)(an-1 + an-2b +…+ bn-2a + bn-1)
- If n
is odd (n = 2k + 1), an + bn =
(a + b)(an-1 – an-2b +an-3b2…-
bn-2a + bn-1)
- (a +
b + c + …)2 = a2 + b2 + c2 +
… + 2(ab + ac + bc + ….)
- Laws
of Exponents (am)(an) = am+n ;
(ab)m = ambm ; (am)n =
amn
Factorization
In
Mathematics, factorization or factoring is defined as the
breaking or decomposition of an entity (for example a number, a matrix, or a
polynomial) into a product of another entity, or factors, which when multiplied
together give the original number or a matrix, etc. This concept we will learn
majorly in our lower secondary classes from 6 to 8.
It is
simply the resolution of an integer or polynomial into factors such that when
multiplied together they will result in original or initial the integer or
polynomial. In the factorisation method, we reduce any algebraic or quadratic
equation into its simpler form, where the equations are represented as the
product of factors instead of expanding the brackets. The factors of any
equation can be an integer, a variable or an algebraic expression itself.
Math Factorization
To the factor, a number means to break it up into numbers
that can be multiplied to get the original number. For example,
24 = 4 × 6
|
4 and 6 are the factors of 24
|
9 = 3 × 3
|
3 is the factor of 9
|
Also, numbers can be factorized
into different combinations. There are different ways to find the Factors
of a Number. To find the factors of an integer is an easy method but to
find the factors of algebraic equations is not that easy. So let us learn to
find the factors of quadratic polynomial.
Factorization in
Algebra
The numbers -12,
-6, -2, -1, 1, 2, 6, and 12 are all factors of 12 because they divide 12
without a remainder. It is an important process in algebra which is used to
simplify expressions, simplify fractions, and solve equations. It is also
called as Algebra factorization.
Factorisation
Of Algebraic Expression
A number or quantity that when multiplied with another
number produces a given number or expression. For example, the factors of 12
are 1, 2, 3, 4, 6 and 12.
12 = 1×12
12 = 2×6
12 = 3×4
Any number can be expressed in the form of its factors as
explained shown above.
In terms of its prime factors 12 can be expressed as:
12 = 2 × 3 × 2 × 1
Similarly an algebraic expression can
also be expressed in the form of its factors. An algebraic expression consists
of variables, constants and operators. An algebraic expression consists of
terms separated by addition operation. Consider the following algebraic
expression:
3xyz–16x2−yz
This
expression consists of 3 terms 3xyz, −16x2 and −yz.
Each
term of this algebraic expression can be expressed in the form of its factors
as:
3xyz=3.x.y.z, −16x2=−1.2.2.2.2.x.x and −yz=−1.y.z.
Algebraic Expressions
can be factorized using many methods. The most common methods used for
factorization of algebraic expressions are:
1.
Factorization using common factors
2.
Factorization by regrouping terms
3.
Factorization using identities
Let us discuss these methods one by one in detail:
1. Factorization
using common factors
In order to factorize an algebraic expression, the highest
common factors of the terms of the given algebraic expression are determined
and then we group the terms accordingly. In simple terms, the reverse process
of expansion of an algebraic expression is its factorization.
To understand this more clearly let us take an example.
Example-
−3y2+18y
Solution- The algebraic expression can be
re-written as
−3y2+18y=−3.y.y+3.6.y
⇒−3y2+18y=−3.y(y–6)
Consider the algebraic
expression -3y( y – 6), if we expand this we will obtain -3y2 +
18y.
Factorization by regrouping terms
In some
algebraic expressions, it is not possible that every term has a common factor.
For instance, consider the algebraic expression 12a + n -na – 12. The terms of
this expression do not have a particular factor in common but the first and
last term have a common factor of ‘12’ similarly second and third term has n as
a common factor. So the terms can be regrouped as:
⇒12a + n – na – 12= 12a – 12 + n – an
⇒12a – 12 – an + n = 12(a -1) –n(a -1)
After regrouping
it can be seen that (a-1) is a common factor in each term,
⇒12a + n -na – 12=(a-1) (12 – n)
Thus by
regrouping terms we can factorize algebraic expressions.
Factorizing Expressions using standard identities
An equality
relation which holds true for all the values of variables in mathematics is
known as an identity. Consider the following identities:
(a+b)2=a2+b2+2ab
(a−b)2=a2+b2−2ab
a2−b2=(a+b)(a−b)
On substituting
any value of a and b, both sides of the given equations remain the same.
Therefore, these equations are identities
Example: Factorize 9x2+4m2+12mx.
Solution:
Observe the given expression carefully. This expression has three terms and all
the terms are positive. Moreover, the first and the second term are perfect
squares. The expression fits the form (a+b)2=a2+b2+2ab where a = 3x, b = 2m.
9x2+4m2+12mx=(3x)2+(2m)2+2.3x.2m
Therefore, 9x2+4m2+12mx=(3x+2m)2
Thus, the
required factorization of 9x2+ 4m2 + 12mx is
(3x + 2m)2 by using standard identities.
Polynomial: A
polynomial is one or more terms that contain only non-negative integer
exponents, and which are combined with addition and subtraction. Note that the
prefix "poly" means "many," so some will define a
polynomial to requre at least two (or even three) terms. We do not follow that
convention here, but consider any individual term to be a polynomial.
Examples: The
following are examples of polynomials.
3, 3 + x, y5 - 1, 2x + 3y - 20z, x
3, 3 + x, y5 - 1, 2x + 3y - 20z, x
Descending Order: A
polynomial is written in descending order if its terms are arranged in order
from largest degree to smallest degree. Note that this is the standard form
for a polynomial; rearranging your polynomials to descending order should be
automatic.
Examples: The
following are polynomials written first in a random order, and then rearranged
to descending order.
x3 + 7 - x5 in descending order is: -x5 + x3 + 7
xy5 - xy + x + x3y6 in descending order is: x3y6 + xy5 - xy + x
x3 + 7 - x5 in descending order is: -x5 + x3 + 7
xy5 - xy + x + x3y6 in descending order is: x3y6 + xy5 - xy + x
Degree of a Polynomial: The
degree of a polynomial is the largest degree of any of its individual terms. If
the polynomial is written in descending order, that will be the degree of the
first term.
Examples: The
following are examples of polynomials, with degree stated.
x3 + 2x + 1 has degree 3.
x5y + x3y2 + xy3 has degree 6.
x3 + 2x + 1 has degree 3.
x5y + x3y2 + xy3 has degree 6.
There
are two ways to divide polynomials but we are going to concentrate on the most
common method here: The algebraic long method or simply the
traditional method of dividing algebraic expression.
Algebraic
Long Method
Here are the steps in dividing polynomials using
the long method:
1. Arrange
the indices of the polynomial in descending order. Replace the missing term(s)
with 0.
2. Divide
the first term of the dividend (the polynomial to be divided) by the first term
of the divisor. This gives the first term of the quotient.
3. Multiply
the divisor by the first term of the quotient.
4.
Subtract the product from the dividend then bring
down the next term. The difference and the next term will be the new dividend.
Note: Remember the rule in subtraction "change the sign of the
subtrahend then proceed to addition".
5. Repeat
step 2 – 4 to find the second term of the quotient.
6. Continue
the process until a remainder is obtained. This can be zero or is of lower
index than the divisor.
If the
divisor is a factor of the dividend, you will obtain a remainder equal to zero.
If the divisor is not a factor of the dividend, you will obtain a remainder
whose index is lower than the index of the divisor.
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